x^2-21x+19=0

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Solution for x^2-21x+19=0 equation: 



x^2-21x+19=0

a = 1; b = -21; c = +19;
Δ = b2-4ac
Δ = -212-4·1·19
Δ = 365
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-21)-\sqrt{365}}{2*1}=\frac{21-\sqrt{365}}{2}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-21)+\sqrt{365}}{2*1}=\frac{21+\sqrt{365}}{2}
$

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